Ilia Denisov
dd61ff1d51
build / dawg (pull_request) Successful in 4m22s
Consolidate the scattered build inputs (dictionaries/english/, dictprep/russian/) into one sources/ tree keyed by the variant labels (scrabble_en/scrabble_ru/ erudit_ru), and move the Russian prep pipeline to tools/. The dawg outputs and their filenames are unchanged — rebuilt byte-identical (en_sowpods/ru_scrabble/ ru_erudit) — so the release artifact and the backend are unaffected. ru_stage2.py OUT_DIR and the ruwords flag defaults are repointed to sources/scrabble_ru/; Makefile / CI / cmd/builddict default / README updated; pipeline intermediates git-ignored. Verified: make dawg byte-identical to the committed baseline, py_compile + go vet of the moved tools. The full Russian regeneration pipeline (pymorphy3/libmorph/orfo PDF) was not run here.
28 lines
984 B
Python
28 lines
984 B
Python
#!/usr/bin/env python3
|
||
"""Fold Ё/ё → Е/е in a word list and de-duplicate — the dictionary prep for "Эрудит".
|
||
|
||
The Эрудит ruleset has no Ё tile and treats Е/Ё as one letter, so its dictionary must be
|
||
folded before the DAWG is built. Folding merges pairs like ёж/еж, hence the de-dup. Output
|
||
is sorted (Russian order over the 32 folded letters) and LF-separated.
|
||
|
||
Run: python3 tools/fold_yo.py sources/scrabble_ru/scrabble.txt > /tmp/ru_erudit_words.txt
|
||
"""
|
||
import sys
|
||
|
||
ORDER = {c: i for i, c in enumerate("абвгдежзийклмнопрстуфхцчшщъыьэюя")} # 32 letters, no ё
|
||
|
||
|
||
def key(w):
|
||
return [ORDER.get(c, 99) for c in w]
|
||
|
||
|
||
def main():
|
||
src = sys.argv[1] if len(sys.argv) > 1 else "/dev/stdin"
|
||
words = {line.strip().replace("ё", "е").replace("Ё", "Е") for line in open(src, encoding="utf-8")}
|
||
words.discard("")
|
||
sys.stdout.write("\n".join(sorted(words, key=key)) + "\n")
|
||
|
||
|
||
if __name__ == "__main__":
|
||
main()
|